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Name: CSIR NET JRF June 2019 Online Form
Exam Full Name:: CSIR-UGC National Eligibility Test 2019
Category: Central Competition Exam
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CSIR NET JRF June 2019 Online Form

Description

Exam Name – CSIR-UGC National Eligibility Test(NET) for Junior Research Fellowship(JRF & for Lectureship(LS)

Council of Scientific and Industrial Research (CSIR), New Delhi invited applications for the Single MCQ Examination (Joint CSIR - UGC Test) for the Award of Junior Research Fellowship (JRF) NET and appointment for Lecturer (NET).

CSIR UGC NET 2019 Exam

 

    • CSIR has scheduled the Joint CSIR UGC NET Exam tentatively on Sunday 16th June 2019 for determining the eligibility of Indian Nationals for the award of Junior Research Fellowships (JRF) and for determining eligibility for appointment of Lecturers (LS) in certain subject areas falling under the faculty of Science & Technology.
    • The award of Junior Research Fellowship (NET) to the successful eligible candidates will depend on their finding admission/placement in a university/ national laboratory/ institution of higher learning and research, as applicable.

Exam Level

National level exam

 Educational Qualification –

(a) Candidates Having Masters in Science Stream(M.SC)/Equivalent Degree with 55% Marks(Gen/OBC Candidates) & 50% Marks(SC/ST/PH Candidates will be eligible for CSIR Examination.

(b) Candidates having Integrated Courses such as B.E/B.Tech/B.Pharma & MBBS Candidates are also eligible for CSIR NET 2018.

How to Apply - Candidates can apply through official site of the CSIR before 18/March/2019.

 

Mode of Selection-   Written Examination

 

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